Question

$(2ax + 1)(3x + 1) = 6a(x + 1)$
and x = 1​

Answer 1

Answer:

(2ax+1)(3x+1)=6a(x+1)

=>[2a(1)+1][3(1)+1]=6a[(1+1)]

=>(2a+1)(3+1)=6a(2)

=>(2a+1)(4)=12a

=>8a+4=12a

=>8a−12a=−4

=>−4a=−4

=>a=1