Question

$( 2m ^{2} + 3n ^{2} ) ^{2}$


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Answer 1

Answer:

tex]\bf\huge\color{blue}\ mathbb{ \star\:hello\: mate!\star}[/tex] we will use the identity 1 here, i.e.,( a + b )² = a² + b² +  ...

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Answer 2

SOLUTION:

$\implies \bf(2m ^{2} + 2n ^{2} )^{2} \\ \\ \implies \bf \: (2m ^{2} + 2n ^{2} )^{2} + (2m ^{2} + 2n ^{2} )^{2} \\ \\ \implies \bf \: 2m ^{2} (2m ^{2} + 2n ^{2} ) + 2n ^{2} (2m ^{2} + 2n ^{2} ) \\ \\ \implies \bf4m ^{4} + 4m ^{2} n ^{2} + 4m ^{2} n ^{2} + 4n ^{4} \\ \\ \implies \bf4m ^{4} + 8m ^{2} n ^{2} + 4n ^{2}$