Math, asked by debjanizoya, 3 months ago


2x   ^{2}  - 3x - k + 2 = 0      \:  \:  \:  \:  \:  \: k =

Answers

Answered by Anonymous
0

Question :-

=> 2x² - 3x - k + 2 = 0

Answer :-

=> 2x² - 3x - k + 2 = 0

=> 2x² - 3x + 2 = 0 + k

=> 2x² - ( 4 - 1 )x + 2 = k

=> 2 - 4x + 1x + 2 = k

=> 2x ( x - 2 ) -1 ( x - 2 ) = k

° k = ( x - 2 ) or ( 2x - 1 )

Let , k = ( x - 2 )

=> x - 2 = 0

=> x = 0 + 2

=> x = 2

Again let , k = ( 2x - 1 )

=> 2x - 1 = 0

=> 2x = 0 + 1

=> x = 1/2 ×

we know that , value of x can not be in decimal , negative or fraction form

° k = ( x - 2 )

@ Lily (=^・ェ・^=)

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