Question

$2x ^{2} + 7 \sqrt{2x} + 12$
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Answer 1

Answer :

$2x {}^{2} + 7 \sqrt{2} x + 12 \\ \\ 2x {}^{2} + 4 \sqrt{2} x + 3 \sqrt{2} x + 12 \\ \\ 2x(x + 2 \sqrt{2} ) + 3 \sqrt{2} (x + 2 \sqrt{2} ) \\ \\ (x + 2 \sqrt{2} )(2x + 3 \sqrt{2} )$

Hence,

Hence, x = - 2√2 or x = -3√2/2

Answer 2

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$2 {x}^{2} + 7 \sqrt{2} x + 12 = 0 \\ \\ 2 {x}^{2} + 4 \sqrt{2} x + 3 \sqrt{2} x + 12 = 0\\ \\ 2x(x + 2 \sqrt{2} )(2x + 3 \sqrt{2} ) = 0$

Hence , X = - 2√2 And -3√2 / 2

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