Question

$2x ^{2} - x + 1 by \: 8 = 0$
WRONG ANSWER WILL BE REPORTED

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Answer 1

Answer:

$\huge \bold{ \color{red}{ \underline{ \color{yellow}{ \underline{ \color{olive}{ \bf \: hope \: it \: help's}}}}}}$

Answer 2

Question:

${2x}^{2} - x + \frac{1}{8}= 0$

Answer:

${2x}^{2} - x + \frac{1}{8} = 0$

$= > \frac{16 {x}^{2} - 8x + 1}{8} = 0$

$= > 16 {x}^{2} - 8x + 1 = 0$

$= > 16 {x}^{2} - 4x - 4x + 1 = 0$

$= > 4x(4x - 1) - (4x - 1) = 0$

$= > (4x - 1)(4x - 1) = 0$

$= > 4x - 1 = 0 = > 4x - 1 = 0$

$= > x = \frac{1}{4} = > x = \frac{1}{4}$