Math, asked by Stinkyslinger, 1 year ago


2x^2 + y^2 + 8z^2 - 2 \sqrt{2} xy + 4 \sqrt{2} yz - 8xz

Answers

Answered by amankumaraman11
1

{ \small{2x^2 + y^2 + 8z^2 - 2 \sqrt{2} xy + 4 \sqrt{2} yz - 8xz}} \\ { \mathtt{\boxed{ \small{  {(  - \sqrt{2} x)}^{2}  +  {(y)}^{2}  +  {(2 \sqrt{2} z)}^{2}  + 2[( -  \sqrt{2}x )(y) + (y)(2 \sqrt{2}z ) + (2 \sqrt{2z} )( -  \sqrt{2} x)]}}}} \\  \\  =  >  { \mathbf{{( -  \sqrt{2}x + y + 2 \sqrt{2} z )}^{2} }}

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