Question

$( {2x - y + z)}^{2}$

Answer 1

hope it helps._______

Answer 2

$\huge\sf\blue{{(2x-y+z)}^{2}}$

Given: $\sf{a = 2x}$

$\sf{b = -y }$

$\sf{c = z }$

$\huge\sf\orange{Simplification-}$

${\underline{\sf{\green{{Main\:Identity: (a+b+c)}^{2}={a}^{2}+{b}^{2}+{c}^{2}+2ab+2bc+2ca}}}}$

$\longrightarrow \sf{{(a-b+c)}^{2}={a}^{2}+{b}^{2}+{c}^{2}-2ab-2bc+2ca}$

$\longrightarrow\sf{{(2x-y+z)}^{2}={2x}^{2}+{y}^{2}+{z}^{2}-2\times\:2x\times\:y-2\times\:2x\times\:y-2\times\:z\times\:2x}}$

$\longrightarrow \sf\green{{(2x-y+z)}^{2}={4x}^{2}+{y}^{2}+{z}^{2}-4xy-2yz+4xz}$