Question

$2y + 3 \div 3y + 2 = 4y + 5 \div 6y + 7$
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Answer 1

$\huge\purple{Required \: Answer :}$

$\frac{2y + 3}{3y + 2} = \frac{4y + 5}{6y + 7} \\ 2y + 3(6y + 7) = 4y + 5(3y + 2) \\ 2y(6y + 7) + 3(6y + 7) = 4y(3y + 2) + 5(3y + 2) \\ 12 {y}^{2} + 14y + 18y + 21 = 12 {y}^{2} + 8y + 15y + 10 \\ \: \: 12 {y}^{2} + 32y + 21 = 12 {y}^{2} + 23y + 10 \\ 32y - 23y + 21 - 10 = 12 {y}^{2} - 12 {y}^{2} \\ 9y + 11 = 0 \\ 9y = - 11 \\ y = \frac{ - 11}{9}$

$\huge\sf\implies{Thanks : ❤}$