Question

$({3}^{ - 3} \times {6}^{2} \times \sqrt{98 } ) \div {5}^{2} \times \sqrt[3]{1 \div 25} \times {15}^{ - 4 \div 3} \times 3 \times \frac{1}{3}$
plz solve

Answer 1

$\frac{{3}^{ - 3} \times {6}^{2} \times \sqrt{98 }}{{5}^{2} \times \sqrt[3]{ \frac{1}{25} } \times {15}^{ \frac{ - 4}{3} } \times {3}^{ \frac{1}{3}}} \\ \\ = \frac{{3}^{ - 3} \times {6}^{2} \times 7\sqrt{2 }}{{5}^{2} \times {5}^{ \frac{ - 2}{3} } \times {5}^{ \frac{ - 4}{3} }\times {3}^{ \frac{ - 4}{3} } \times {3}^{ \frac{1}{3}}} \\ \\ = \frac{{3}^{ - 3} \times {3}^{2} \times {2}^{2} \times {2}^{ \frac{1}{2} } \times 7}{{5}^{2} \times {5}^{ \frac{ - 2}{3} } \times {5}^{ \frac{ - 4}{3} }\times {3}^{ \frac{ - 4}{3} } \times {3}^{ \frac{1}{3}}} \\ \\ = {3}^{( - 3 + 2 + \frac{4}{3} - \frac{1}{3}) } \times {2}^{(2 + \frac{1}{2}) } \times 7 \times {5}^{ - 2 + \frac{2}{3} + \frac{4}{3} } \\ \\ = {3}^{0} \times {2}^{ \frac{5}{2} } \times 7 \times {5}^{0} \\ \\ = 4 \sqrt{2} \times 7 \\ \\ = 28 \sqrt{2}$

Answer 2

$\frac{{3}^{ - 3} \times {6}^{2} \times \sqrt{98 }}{{5}^{2} \times \sqrt[3]{ \frac{1}{25} } \times {15}^{ \frac{ - 4}{3} } \times {3}^{ \frac{1}{3}}} \\ \\ = \frac{{3}^{ - 3} \times {6}^{2} \times 7\sqrt{2 }}{{5}^{2} \times {5}^{ \frac{ - 2}{3} } \times {5}^{ \frac{ - 4}{3} }\times {3}^{ \frac{ - 4}{3} } \times {3}^{ \frac{1}{3}}} \\ \\ = \frac{{3}^{ - 3} \times {3}^{2} \times {2}^{2} \times {2}^{ \frac{1}{2} } \times 7}{{5}^{2} \times {5}^{ \frac{ - 2}{3} } \times {5}^{ \frac{ - 4}{3} }\times {3}^{ \frac{ - 4}{3} } \times {3}^{ \frac{1}{3}}} \\ \\ = {3}^{( - 3 + 2 + \frac{4}{3} - \frac{1}{3}) } \times {2}^{(2 + \frac{1}{2}) } \times 7 \times {5}^{ - 2 + \frac{2}{3} + \frac{4}{3} } \\ \\ = {3}^{0} \times {2}^{ \frac{5}{2} } \times 7 \times {5}^{0} \\ \\ = 4 \sqrt{2} \times 7 \\ \\ = 28 \sqrt{2}$