Question

(
$(3 \div 7 )^{4} \times (3 \div 7 )}^{5} = (3 \div 7}2m + 1$
​

Answer 1

${ (\frac{3}{7} )}^{4} \times {( \frac{3}{7} )}^{5} = {( \frac{3}{7} )}^{2m + 1} \\ \\ = > {( \frac{3}{7} )}^{4 + 5} = {( \frac{3}{7}) }^{2m + 1}$

On comparing :

4 + 5 = 2m + 1

=> 2m = 8

=> m = 4

I hope it will be helpful for you ☺️