Question

$3 \sqrt{5 {x }^{2} } + 25x - 10 \sqrt{5 = 0}$

ans by factorization method ​

Answer 1

$\textbf{\underline{\red{\large{Step by step Explanation:-}}}}$

$\textit{\underline{Given,,}}$

$\mathtt{a=3\sqrt{5},,b=25,,c=10\sqrt{5}}$

$\mathcal{\underline{Hence,,}}$

$\mathtt{x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}}$

$\mathtt{\implies{x=\frac{-25\pm\sqrt{25^{2}-4\times{3\sqrt{5}}\times{-10\sqrt{5}}}}{2\times{3\sqrt{5}}}}}$

$\mathtt{\implies{x=\frac{-25\pm\sqrt{625-(4)(3)(5)(-10)}}{6\sqrt{5}}}}$

$\mathtt{\implies{x=\frac{-25\pm\sqrt{625+600}}{6\sqrt{5}}}}$

$\mathtt{\implies{x=\frac{-25\pm\sqrt{1225}}{6\sqrt{5}}}}$

$\mathtt{\implies{x=\frac{-25\pm{35}}{6\sqrt{5}}}}$

$\mathtt{x_{1}=\frac{-25+35}{6\sqrt{5}}}$

$\mathtt{\implies{x_{1}=\frac{10}{6\sqrt{5}}}}$

$\mathtt{\implies{x_{1}=\frac{5}{3\sqrt{5}}}}$

$\mathtt{\implies{x_{1}=\frac{\sqrt{5}}{3}}}$

$\mathtt{x_{2}=\frac{-25-35}{6\sqrt{5}}}$

$\mathtt{\implies{x_{2}=\frac{-60}{6\sqrt{5}}}}$

$\mathtt{\implies{x_{2}=\frac{-10}{\sqrt{5}}}}$

$\mathtt{\implies{x_{2}=-2\sqrt{5}}}$

$\mathit{\underline{Hence,,}}$

$\mathtt{x_{1}=\frac{\sqrt{5}}{3}}$

$\mathtt{x_{2}=-2\sqrt{5}}$

$\textbf{\pink{\large{Hope it helps you.. thanks}}}$

Answer 2

Step-by-step explanation:

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