Question

$3 {x }^{2} - 2 \sqrt{6} x + 2 = 0$
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Answer 1

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Answer 2

$3 {x }^{2} - 2 \sqrt{6} x + 2 = 0$

$3 {x}^{2} - \sqrt{6} x - \sqrt{6} x + 2 = 0 \\ \sqrt{3} x( \sqrt{3} x - \sqrt{2} ) - \sqrt{2} ( \sqrt{3} x - \sqrt{2} ) = 0 \\ {( \sqrt{3} x - \sqrt{2}) }^{2} = 0 \\ x = \sqrt{ \frac{2}{3} }$

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