Math, asked by preetiahir, 1 year ago



3x   {?}^{2}  - 2 \sqrt{6} x + 2 = 0
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Answers

Answered by puja77
1
heya Mate see the above attachment

here the value of x = 2/√3 and 2/√3

hope it helps you
Attachments:

preetiahir: thank u
puja77: welcm dear
Answered by rakeshmohata
0
Hope u like my process
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3 {x}^{2}  - 2 \sqrt{6} x + 2 = 0 \\  \\ or. \:  \:  {( \sqrt{3}x) }^{2}  - 2( \sqrt{3} x)( \sqrt{2} ) +  {( \sqrt{2}) }^{2}  = 0 \\  \\ or. \:  \: ( \sqrt{3} x -  \sqrt{2} )^{2}  = 0 \\  \\ or. \:  \:  \sqrt{3} x -  \sqrt{2}  = 0 \\  \\ or. \:  \:  \sqrt{3} x =  \sqrt{2}  \\  \\ or. \:  \: x =  \sqrt{ \frac{2 }{3} }
Hope this is ur required answer
Proud to help you
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