Question

${3x}^{2} + {2y}^{2}$

Answer 1

$\text{Your answer }$

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${3x}^{2} + {2y}^{2} = 0 \\ \\ Let's \: find \: the \:solutions \\ Let \:x = 0 \\ 0 + {2y}^{2} = 0 \\ {y}^{2} = \frac{1}{2} \\ \\ Let \: x = 2 \\ 3{2}^{2} + {2y}^{2} = 0 \\ 12 + {2y}^{2} = 0 \\ {2y}^{2} = - 12 \\ {y}^{2} = \frac{-12}{2} \\ {y}^{2} = - 6$

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