Question

${3y}^{2} - 2y - 1$
${2x}^{2} + x - 1$
find the factors of the following polynomials given above ​

Answer 1

Answer:

$3 {y}^{2} - 2y - 1$

$3 {y}^{2} - 3y +y - 1$

$3y(y - 1) + 1(y - 1)$

(3y+1)(y-1)

thus factors are -1/3,1

$2 {x}^{2} + x - 1$

$2 {x}^{2} + 2x - x - 1$

2x(x+1)-1(x+1)

(2x-1)(x+1)

thus factors are 1/2,-1

Answer 2

Answer:

what happened?

why you blocked me?