Question

$(3y^{2} + 5y - 4) - (8y - y^{2} - 4)$
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Answer 1

Answer:

(3y² + 5y - 4)-(8y - y² - 4 )

3y² + 5y - 4 - 8y + y² + 4

4y² - 3y

:-)

Answer 2

Answer :-

1. (3y² + 5y - 4) - (8y - y² - 4)

= 3y² + 5y - 4 - 8y + y² + 4

= 4y² - 3y

= y(4y - 3)

Now, solving the term,

.°. Either y = 0 or, (4y - 3) = 0

=> 4y - 3 = 0

=> 4y = 3

=> y = 3/4

.°. The value of y is 0 or 3/4.

______________________________

Verifying the equation,

Putting the value of x = 0

= (3 × 0² + 5 × 0 - 4) - (8 × 0 - 0² - 4)

= (3 × 0 + 0 - 4) - (0 - 0 - 4)

= (0 + 0 - 4) - (-4)

= -4 + 4

= 0

Putting another value of x = 3/4

= (3 × 3/4² + 5 × 3/4 - 4) - (8 × 3/4 - 3/4² - 4)

= (3 × 9/16 + 15/4 - 4) - (6 - 9/16 - 4)

= (27/16 + 15/4 - 4) - (6 - 9/16 - 4)

= (27 + 60 - 64/16) - (96 - 9 - 64/16)

= (23/16) - (23/16)

= 23/16 - 23/16

= 0

.°. Hence, Verified.