Math, asked by anuskasen7, 10 months ago


(4 +  \sqrt{32} ) \sqrt{64}  - 4 \sqrt{2}
solve this​

Answers

Answered by Anonymous
1

( 4 +  \sqrt{32})( \sqrt{64 - 4 \sqrt{2  } }  \\ (4 +  \sqrt{2 \times 2 \times 2 \times 2 \times 2} )( \sqrt{2 \times 2 \times 2 \times  \times 2 \times 2 \times 2 - 4 \sqrt{2)  } }  \\( 4 + 4  \sqrt{2} )(8 - 4 \sqrt{2} ) \\ 8 \sqrt{2 }  \times 4 \sqrt{2 }  \\  = 64 \: is \: the \: answer

Attachments:
Answered by King0210
2

Answer:

Hey Friend...

Hope this Helps...

Attachments:
Similar questions