Question

${4}^{x } = \sqrt{2 ^{3y} }$
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Answer 1

Step-by-step explanation:

${4}^{x} = \sqrt{ {2}^{3y} }$

${ ({4}^{x} )}^{2} = {2}^{3y}$

${( {( {2}^{2} )}^{x} )}^{2} = {2}^{3y}$

${2}^{4x} = {2}^{3y}$

4x=3y

x=3y/4