Question

$40 \div (1 + (9 + 10)$
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Answer 1

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$40 \div (1 + (9 + 10)$

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$➩40 \div (1 + (9 + 10)$

$➩40 \div (1 + 19)$

$➩40 \div (20)$

$➩ \frac{40}{20} = 2$

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Answer 2

Answer:

$40 \div (1 + (9 + 10))$

$= 40 \div (1 + 19)$

$= 40 \div 20$

$= 2$

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