Question

${4s}^{2} - 4s + 1 = 0$
How to solve
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Answer 1

4s² - 4s + 1 = 0

4s² - 2s - 2s + 1= 0

2s(2s - 1) - 1(2s - 1) = 0

(2s - 1)(2s -1) = 0

(2s - 1)² = 0

2s - 1 = √0

2s - 1 = 0

2s = 1

s = 1/2

Answer 2

Step-by-step explanation:

We are given an Quadratic equation

$\implies{\mathsf{ 4s^{2} - 4s + 1 = 0}}$

By Middle term splitting

$\implies{\mathsf{ 4s^{2} -2s - 2s +1 = 0 }}$

$\implies{\mathsf{ 2s ( 2s - 1) -1(2s -1)= 0 }}$

$\implies{\mathsf{ ( 2s - 1) \times ( 2s - 1) = 0 }}$

Equate the factors to zero

$\implies{\mathsf{ ( 2s - 1) = 0 }}$

$\implies{\mathsf{ s = \frac{1}{2} }}$

So the values of S are 1/2 , 1/2

2] Method

Using Quadratic Formula

$\boxed{\implies{\mathsf{ X = \frac{-b \pm \sqrt{b^{2} -4ac }}{2a} }}}$

here a,b,c are the co-efficients of x variable

Ax² + bx + c = 0

$\boxed{\bigstar{\mathsf{ Any}}}$ quadratic equation have two zeroes or roots