Question

${4x}^{2} + 15x- 4$

Answer 1

$4 {x}^{2} + 15x - 4 \\ 4 {x}^{2} + (16 - 1)x - 4 \\ 4 {x}^{2} + 16x - x - 4 \\ 4x(x + 4) - 1(x + 4) \\ (4x - 1)(x + 4)$

Answer 2

heya....

Here is your answer.....

$4 {x}^{2} + 15x - 4$


$4 {x}^{2} + (16 - 1)x - 4$


$4 {x}^{2} + 16x - x - 4$


$4(x + 4) - 1(x + 4)$


$(4x - 1)(x + 4)$


It may help you....☺☺