Question

$4x {}^{2} - 4x + 1 - 9$
​

Answer 1

Answer:

4x^2-4x-8

4x^2-8x+4x-8

4x(x-2)+4(x-2)

(4x+4)(x-2)

Step-by-step explanation:

Answer 2

Step-by-step explanation:

${4x}^{2} - 4x + 1 - 9$

${4x}^{2} - 4x - 8 = 0$

$4( {x}^{2} - x - 2) = 0$

${x}^{2} - x - 2 = 0$

${x}^{2} - 2x + x - 2$

$x(x - 2) + 1(x - 2)$

$(x - 2)(x + 1)$