Math, asked by bablutomar1980, 7 months ago


4x {}^{3 }  - 5x {}^{2}  - 6x + 7when \: x = 2

Answers

Answered by TheInnocentSoul
0

Answer:

refer to the attachment

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Answered by ƁƦƛƖƝԼƳƜƛƦƦƖƠƦ
2

Step-by-step explanation:

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4x {}^{3 } - 5x {}^{2} - 6x + 7 \\ x = 2

 = 4 ({2}^{3} ) + 5( {2}^{2} ) - 6 \times (2) + 7

 = 4(8) + 5(4) - 12 + 7

 = 32 + 20 - 5

 = 32 + 15

 = 47

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