Math, asked by satyamsahu70, 1 year ago


4x - 3x(x - 1) - 2x ^{2}

Answers

Answered by kapil913
0
QUESTION::

4x - 3x(x - 1) - 2x ^{2}
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ANSWER::

4x - 3x(x - 1) - 2x ^{2}

=4x + (-3x × x) + (-3x × -1) - {2x}^{2}

=  4x - {3x}^{2} + 3x - {2x}^{2}

( NOW WE HAVE TO INTERCHANGE THE DIGITS FOR MORE CONVENIENCE )

=  4x + 3x- {3x}^{2} - {2x}^{2}

=  7x - {5x}^{2}

SO, ANSWER IS :-.  7x - {5x}^{2}

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