Question

at a depth of 1000m in an ocean (1). what is absolute pressure (2). the gauge pressure (3)find the firce acting of the window of area 20*20cm of a submarine at this depth the interior of which it's maintained at sea level

Answer 1

Answer:

Here h = 1000 m and ρ = 1.03 × 103 kg m-3.

(a) From Eq. P2 − P1= ρgh, absolute pressure

P = Pa + ρgh

= 1.01 × 105 Pa+ 1.03 × 103 kg m–3 × 10 m s–2 × 1000 m

= 104.01 × 105 Pa

≈ 104 atm

(b) Gauge pressure is P − Pa = ρgh = Pg

Pg = 1.03 × 103 kg m–3 × 10 ms2 × 1000 m

= 103 × 105 Pa

≈ 103 atm

(c) The pressure outside the submarine isP = Pa + ρgh and the pressure inside it isPa. Hence, the net pressure acting on thewindow is gauge pressure, Pg = ρgh. Sincethe area of the window is A = 0.04 m2, theforce acting on it is

F = Pg A = (103 × 105 Pa) × 0.04 m2 = 4.12 × 105 N

Answer 2

Answer:

Is it right

Explanation:

☺☺☺☺done!!!