Question

$5 + 2 \sqrt{3} \div 7 + 4 \sqrt{3}$
cojugate

Answer 1

Your answer above in the attachment ...

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Answer 2

$5 + 2 \sqrt{3} \div 7 + 4 \sqrt{3} \\ \frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} } \times \frac{7 - 4 \sqrt{3} }{7 - 4 \sqrt{3} } \\ \frac{35 - 20 \sqrt{3} + 14 \sqrt{3} - 24}{( {7}^{2} - ( { {4}^{2} \sqrt{3} }^{2} )} \\ \frac{11 - 6 \sqrt{3} }{49 - 48} \\ 11 - 6 \sqrt{3}$