Question

$5 + 2\sqrt{3} \div 7 + 4 \sqrt{3}$
conjugate

Answer 1

heya..!!!


$\frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} } \\ \\ = > \frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} } \times \frac{7 - 4 \sqrt{3} }{7 - 4 \sqrt{3} } \\ \\ = > \frac{(5 + 2 \sqrt{3} )(7 - 4 \sqrt{3}) }{ {7}^{2} - {(4 \sqrt{3}) }^{2} } \\ \\ = > \frac{35 - 20 \sqrt{3} + 14 \sqrt{3} - 24}{49 - 48} \\ \\ = > \frac{11 - 6 \sqrt{3} }{1} = 11 - 6 \sqrt{3}$


I HOPE ITS HELP YOU,

Answer 2

Hello dear friend ..
Ur answer is here
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$given \: \: \frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} } \\ \\ sol. \\ = > \frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} } \times \frac{7 - 4 \sqrt{3} }{7 - 4 \sqrt{3} } \\ \\ = > \frac{35 - 20 \sqrt{3 } + 14 \sqrt{3} - 8( \sqrt{3} \times \sqrt{3}) }{( {7)}^{2} - ( {4 \sqrt{3} )}^{2} } \\ \\ = > \frac{(35 - 24) - 6 \sqrt{3} }{49 - 48} \\ \\ = > 11 - 6 \sqrt{3} \: \: \: answer$
Hope it's helps you.
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