Math, asked by aritrik56, 5 hours ago


( - 5 {x}^{2}) \times (  -  \frac{2}{3}x {y}^{2}z) \times ( \frac{8}{15}xy {z}^{2}) \times ( -  \frac{1}{4}z)

Answers

Answered by santoshpatil922
0

this question answer is

=(-5×2÷3×8÷15×1÷4)×x^3×y^3×z^3

=(-80÷180)×x^3×y^3×z^4

=-4xx^3×y^3×z^4÷9

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