Question

$5x^2-4x-3=0$
$\mathfrak\pink{Answer \: in \: brief}$
spammer go away​

Answer 1

Answer:

hope this will helps you

Answer 2

$\tt\huge\purple{hello!!!}$

HERE IS UR ANSWER

$_____________________________$

$5 {x}^{2} - 4x - 3 = 0$

$\fbox{By discriminant method}$

$d = {b}^{2} - 4ac$

$d = {( - 4)}^{2} - 4(5)( - 3) \\ = 16 - ( - 60) \\ = 16 + 60 \\ =76$

now,

$x = \frac{ - b + \sqrt{d} }{2a} \: and \: x = \frac{ - b - \sqrt{d} }{2a} \\ x = \frac{4 + 2 \sqrt{19} }{10} \: and \: x = \frac{4 - 2 \sqrt{19} }{10} \\ x = \frac{2 + \sqrt{19} }{5} \: and \: x = \frac{2 - \sqrt{19} }{5}$

$\bold\pink{thanKs!!}$

__________________________