Question

${6^{-1} +(3/2)^{-2} }^{-1}$

Answer 1

Step-by-step explanation:

-21/162 is the correct answer

Answer 2

Step-by-step explanation:

${6}^{ - 1} + { { \frac{3}{2} }^{ - 2} }^{ - 1} = {6}^{ - 1} + { \frac{3}{2} }^{ (- 2 \times - 1)} \\ = \frac{1}{6} + {( \frac{3}{2} )}^{2} = \frac{1}{6} + \frac{9}{4} = \frac{2 + 27}{12} \\ = \frac{29}{12}$