Question

$(6 + 2q) ^{3}$
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please answer​

Answer 1

Using the identity,

${(x + y)}^{3} = {x}^{3} + {y}^{3} + 3 {x}^{2}y + 3x {y}^{2}$

$= {6}^{3} + {2q}^{3} + 3 {(6)}^{2}y + 18 {y}^{2}$

$= 216 + {8q}^{3} + 108y + 18 {y}^{2}$

Answer 2

${HELLO!!}$

Alexa is here...

${(6 + 2q)}^{3} \\ {6}^{3} + {2q}^{3} - 3 \times 6 \times 2q( 6+ 2q) \\216 + {8q}^{3} - 36q(6 + 2q) \\ 216 + {8q}^{3} - 216 - 72q \\ {8q}^{ 3} - 72q$

Hope it helps you