Question

$6(a + b) {}^{2} + 5(a {}^{2} - b {}^{2} ) - 6(a - b) {}^{2}$

Answer 1

Let (a + b) = x
(a - b) = y


6x² - 5(a² - b²) - 6y²


6x² - 5(a + b)(a - b) - 6y²

6x² - 5xy - 6y²

6x² - 9xy + 4xy - 6y²

3x(2x - 3y) + 2y(2x - 3y)

(3x + 2y) (2x - 3y)

(3a + 3b + 2a - 2b)(2a + 2b - 3a + 3b)

(5a + b)(5b - a)




$.$



I hope this will help you


(-:

Answer 2

Hello friends!!

Here is your answer :

Let ( a + b) = m

( a - b) = n

We know that,

a² - b² = ( a - b) ( a + b)

$6 {(a + b)}^{2} + 5( {a}^{2} - {b}^{2} ) - 6 {(a - b)}^{2}$

$6 {m}^{2} + 5(a + b)(a - b) - 6 {n}^{2}$

$6 {m}^{2} + 5mn - 6 {n}^{2}$

6m² + 9mn - 4mn - 6n²

3m ( 2m + 3n) - 2n ( 2m + 3n)

( 2m + 3n) ( 3m - 2n)

[ 2(a+b) +3(a-b)] [3(a+b) - 2(a-b)]

[ 2a + 2b +3a - 3b] [ 3a + 3b - 2a + 2b]

( 5a - b) ( 5b - a)

Hope it helps you..

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