Question

$6x {}^{2} - 7x - 13 = 0 \: factorisation \: method$

Answer 1

Heya !!

6X² - 7X - 13 = 0

6X² - 13X + 6X - 13 = 0

X ( 6x - 13 ) + 1 ( 6X - 13 ) = 0.


( 6X - 13 ) ( X + 1 ) = 0




( 6X - 13 ) = 0 OR ( X + 1 ) = 0



X = 13/6 OR X = -1

Answer 2

6x² - 7x - 13 = 0




=> 6x² - ( 13 - 6 ) x - 13 = 0


=> 6x² - 13x + 6x - 13 = 0


=> x(6x - 13 ) + 1( 6x - 13 ) = 0


=> ( x + 1 ) ( 6x - 13 ) = 0



$\mathbf{By \: \: Zero \: \: Product \: \: Rule } \\ \\ x + 1 = 0 \: \: \: \: \: \: \: or \: \: \: \: \: \: 6x - 13 = 0 \\ \\ x = - 1 \: \: \: \: \: or \: \: \: \: x = \frac{13}{6}$