Question

$6x {}^{2} + x + 2$
plz answer to this question​

Answer 1

Answer:

6x2−x−2=0

6x2−4x+3x−2=0

2x(3x−2)+(3x−2)1=0

(2x+1)(3x−2)=0

2x+1 = 0 or 3x-2 = 0 

x = -1/2 , x=2/3.

Step-by-step explanation:

I hope it will help you.

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