Question

${6y}^{3}(2y - 3) - 4y(4y - 6)$
Factorise

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Answer 1

Answer: $2y(3y^{2}-4)(2y-3)$

Step-by-step explanation:

$6y^{3}(2y-3)-4y(4y-6)\\ =6y^{3}(2y-3)-4y*2(2y-3)\\=6y^{3}(2y-3)-8y(2y-3)\\=(6y^{3}-8y)(2y-3)\\=2y(3y^{2}-4)(2y-3)$

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Answer 2

Step-by-step explanation:

take common

$2y(2y - 3)$

from both part and you get

$2y(2y - 3)(3 {y}^{2} - 2)$

this is the factorisation.