Question

$7 {x}^{2} + 49x + 84$

Answer 1

$7 {x}^{2} + 49x + 84 = 0 \\ {x}^{2} + 7x + 12 = 0 \\ {x}^{2} + 4x + 3x + 12 =0 \\ x(x + 4) + 3(x + 4) = 0 \\ x + 4 = 0 \\ x = - 4 \\ \\ x + 3 = 0 \\ x = - 3$

Answer 2

ALOHA , SAT SRI AKAL , NAMASTE.....My dear frnd☺
HERE IS UR ANSWER⬇️
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▶️7x^2 +49x + 84 =0
7(x^2 + 7 + 12 ) = 0
x^2+ 4x + 3x+ 12 =0.
x(x+4) +3(x+4) = 0
(x+4) (x+3).
x = - 4 & x = - 3
So , The zeroes are -3,-4✔
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HOPE IT HELPS U✌✌