Question

$(7g^{2} +6g-8) - (5x^{2} - 2g + 4)$

Answer 1

Step-by-step explanation:

(1): "g2" was replaced by "g^2". 1 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

(((0-(7•(g2)))-4g)+5)+(((0-(2•3g2))-2g)-4)

STEP

2

:

Equation at the end of step

2

:

(((0 - 7g2) - 4g) + 5) + (-6g2 - 2g - 4)

STEP

3

:

STEP

4

:

Pulling out like terms

4.1 Pull out like factors :

-13g2 - 6g + 1 = -1 • (13g2 + 6g - 1)

Trying to factor by splitting the middle term

4.2 Factoring 13g2 + 6g - 1

The first term is, 13g2 its coefficient is 13 .

The middle term is, +6g its coefficient is 6 .

The last term, "the constant", is -1

Step-1 : Multiply the coefficient of the first term by the constant 13 • -1 = -13

Step-2 : Find two factors of -13 whose sum equals the coefficient of the middle term, which is 6 .

-13 + 1 = -12

-1 + 13 = 12

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Final result :

-13g2 - 6g + 1