Math, asked by cyclewarlol14, 7 months ago


 8 - 2 \sqrt{3}  \div 2 \sqrt{3 - 1}

Answers

Answered by adityarawat28122004
0

Answer:

8-√3/2

Step-by-step explanation:

8 - 2 \sqrt{3}   \div 2 \sqrt{3 - 1}  \\  = 8 -  \sqrt{2  \times 2 \times 3}  \div  \sqrt{2 \times 2 \times 2}  \\  = 8 -  \sqrt{12}  \div  \sqrt{8}  \\  = 8  -  \sqrt{12 \div 8}   \\  = 8 -  \sqrt{3 \div 2}

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If it is wrong answer so sorry and delete my answer

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