Question

$8(x - 1) \geqslant 10(x + 1)$
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Answer 1

Step-by-step explanation:

8x-8>=10x+10

-8-10>=10x-8x

-18>=2x

-9>=x

Answer 2

Answer:

Given that

$8(x - 1) \geqslant 10(x + 1)$

We can solve this inequality by applying all the rules used in inequality while finding the value of x like as while multiplying or dividing a negative term in both side of the inequality then sign of an inequation will be changed and some more properties may be used.

So,it can be solved by following method:-

$8(x - 1) \geqslant 10(x + 1) \\ \implies8x - 8 \geqslant 10x + 10 \\ \implies - 8 - 10 \geqslant 10x - 8x \\ \implies - 18 \geqslant 2x \\ \implies x \leqslant \frac{ - 18}{2} \\ \implies x \leqslant - 9 \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed {\boxed{ANSWER}}$

So ,

lt gives that value of x will be

$x \leqslant - 9$