Question

$8a3 + b3 + 12a2b + 6ab2$
​

Answer 1

$8 {a}^{3} + {b}^{3} + 12 {a}^{2} b + 6a {b}^{2} \\ = {(2a)}^{3} + {b}^{3} + 3 \times {(2a)}^{2} \times b + 3 \times 2a \times {b}^{2} \\ = {(2a - b)}^{3}$

Answer 2

${ \bold{ \red{ 8 {a}^{3} + {b}^{3} + 12 {a}^{2} b + 3a {b}^{2} }}}$

${ \bold{ \red{ = {(2a)}^{3} + {(b)}^{3} + 3 {(2a)}^{2} (b) + 3 (2a) ( {b}^{2} )}}}$

${ \boxed{ \boxed{ \bold{ \red{ {(2a + b)}^{3}}}}}}$