Question

$8x { }^{2} -4$

solve by quadractic equation​

Answer 1

Answer:

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$8 {x}^{2} - 4 = 0 \\ 8 {x}^{2} = 4 \\ {x }^{2} = \frac{1}{2} \\ x = \sqrt{ \frac{1}{2} } \: - \sqrt{ \frac{1}{2} }$

Answer 2

Answer:

8x^2-4=0

(2x√2)^2 - 2^2=0

(2x√2+2)(2x√2-2)=0

x= -1/√2 , 1/√2

Explanation:

by identity a^2-b^2= (a+b)(a-b)