Question

$9( \frac{3 + y}{3} )$
calculate and tell me

Answer 1

Hola Mate!!

Your answer :-

$= > 9( \frac{3 + y}{3} ) = 0\\ \\ = > 9( \frac{3}{3} + \frac{y}{3} ) = 0 \\ \\ = > 9 \times \frac{3}{3} + 9 \times\frac{y}{3} = 0 \\ \\ = > 9 + 3y = 0 \\ \\ = > 3y = 0 - 9 \\ \\ = > y = \frac{ - 9}{3} \\ \\ = > y = - 3$

↪ Hence, your answer is - 3

Hope it helps!!