Question

$9 \times 81^{x} = 27 ^{2 - x}$
Solve the mathematics question.​

Answer 1

Answer:

$\huge{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}$

$9 \times 81^{x} = 27 ^{2 - x}$

$= > {3}^{2} \times {3}^{4x} = {3}^{6 - 3x} \\ \\ = > {3}^{2 + 4x} = {3}^{6 - 3x}$

Equating powers

==> 2+4x = 6−3x

==> 7x=4

==> x= 4/7

$x = \frac{4}{7}$

Answer 2

==> x= 4/7

$x = 4 \div 7$


= 4/7

$\huge\bold\star\red{@RiyaMahta}\star$
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