Question

$a ^{2} \div (b + c) = b^{2} \div (c + a) = c ^{2} \div (a + b) = 1 \: \: \: \: \: \frac{1}{1 + a } + \frac{1}{1 + b} + \frac{1}{a + c} = 1$
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Answer 1

Answer:

a ^{2} \div (b + c) = b^{2} \div (c + a) = c ^{2} \div (a + b) = 1 \: \: \: \: \: \frac{1}{1 + a } + \frac{1}{1 + b} + \frac{1}{a + c} = 1a

2

÷(b+c)=b

2

÷(c+a)=c

2

÷(a+b)=1

1+a

1

+

1+b

1

+

a+c

1

=1