Question

$(a + 3b + {4c)}^{2}$

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Answer 1

Here the sum is (2a+3b+4c)^2

for this the formula is (a+b+c)^2 = (2a)^2+(3b)^2+(4c)^2+2(2a)(3b)+2(3b)(4c)+2(4c)(2a)

solution = 4a^2+9b^2+16c^2+12ab+24bc+16ac

Answer 2

hope it is use full ✌✌✌✌✌✌✌✌