Math, asked by pinkymehra27, 4 months ago


 {a}^{4}  +  \: 2 {a}^{2}  {b}^{2}  +  {b}^{2}
plz answer this q ... plz plz pl ​

Answers

Answered by PharohX
2

Step-by-step explanation:

 {a}^{4} + \: 2 {a}^{2} {b}^{2} + {b}^{2}  \\  \\  {a}^{4}  + 2 {a}^{2}  {b}^{2}  +  {b}^{4}  -  {b}^{4}  +  {b }^{2}  \\  \\ ( {a}^{2}  +  {b}^{2} ) {}^{2}  -  {b}^{2} ({b}^{2}  - 1) \\  \\ ( {a}^{2}  +  {b}^{2} ) {}^{2}  -  {b}^{2}  [\sqrt{( {b}^{2} - 1) }] {}^{2}   \\  \\ ( {a}^{2}  +  {b}^{2} ) {}^{2}  - [ {b} \sqrt{( {b}^{2} - 1) }]{}^{2}  \\  \\  [ {a}^{2} +  {b}^{2}  + b \sqrt{ {b}^{2} - 1 }  ][ {a}^{2}  +  {b}^{2} - b \sqrt{ {b}^{2}  - 1}  ]

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