Physics, asked by itzDaku, 1 year ago


a \: function \: f( \theta) \: is \: defined \: as \ratio

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Answered by Anonymous
3

\green{ \bf\huge{ Answer }}

f( \theta) = 1 -  \theta +  \frac{ { \theta}^{2} }{2 !}  -  \frac{ { \theta}^{3} }{3!}  +  \frac{  { \theta}^{4} }{4!} ......

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