Math, asked by bhavishachawla02, 2 months ago


a =  \sqrt{2 }  - 1 \\ find(1 \div a)

Answers

Answered by MathLoverHannu
65

Answer:

 \tt \huge   \red {\frac{ \sqrt{2}  + 1}{3} }

Step-by-step explanation:

 \tt \huge1 \div a =  \frac{1}{ \sqrt{2} - 1 }

Let Rationalise them ☺️

 \tt \huge  \frac{1}{ \sqrt{2} - 1 } \times  \frac{ \sqrt{2} + 1 }{ \sqrt{2}   + 1 } \\  \\  \tt \huge \to \frac{ \sqrt{2} + 1 }{ {( \sqrt{2}) }^{2} +  {(1)}^{2}  }  \\  \\  \tt \huge \to \frac{ \sqrt{2} + 1 }{2 + 1}  =  \frac{ \sqrt{2}  + 1}{3}

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