Question

$ab {x}^{2} + ( {b}^{2} - ac)x - bc$
​

Answer 1

Step-by-step explanation:

Given: abx

2

+(b

2

−ac)x−bc=0

Factorizing the given equation,

⟹abx

2

+b

2

x−acx−bc=0

⟹bx(ax+b)−c(ax+b)=0

⟹(bx−c)(ax+b)=0

Solving the above equation for x, we get

⟹(bx−c)=0 or (ax+b)=0

⟹x=

b

c

or x=

a

−b

Answer 2

$\green{\bold{\underline{ ☆ UPSC-ASPIRANT ☆} }}$

$\red{\bold{\underline{\underline{QUESTION:-}}}}$

Q:-

$ab {x}^{2} + ( {b}^{2} - ac)x - bc$

$\huge\tt\underline\blue{ANSWER }$

------>>>>Here is your answer<<<<--------

$➪ab {x}^{2} + ( {b}^{2} - ac)x - bc$

$➪ab {x}^{2} + {b}^{2} x - acx - bc$

$➪bx(ax + b) - c(ax + b) - bc$

HOPE IT HELPS YOU..

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Thankyou:)