Question

$abx^{2} + (b^{2} - ac)x - bc = 0$
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Answer 1

Answer:

Hey mate,

Here is ur answer.....

abx²+(b²-ac)x-bc

= abx²+b²x-acx-bc

= bx(ax+b)-c(ax+b)

= (bx-c) (ax+b)

Hope this helps you and if then please follow me and mark me as branliest......

Answer 2

♡ Solution =>

Answer:-

Given =>

▪︎ abx²+(b²-ac)x-bc=0

Explanation =>

abx²+(b²-ac)x-bc=0

= abx²+b²x-acx-bc=0

= abx²-acx+b²x-bc=0

= ax( bx-c) +b(bx-c)=0

= (bx-c) ( ax+b)=0

= bx-c=0, ax+b=0

=bx=c, ax=-b

x= c/b , x= -b/a

hope IT HELPs....